find namank in Numerology using C Language
Find Namank in Numerology using C Language
We are sharing, how to find Namank in Numerology using C Language. In Numerlogy, Bhagyank, Mulank & Namank are important factors.
Find Mulank : The Sum of the digits of your date of birth. It also should be less than 9. For example, your date of birth is 29th, then your mulank is 2 (2+9=11, 1+1=2)
Find Bhagyank : The Sum of digits of your complete date of birth. It also should be less than 9 . For example, your date of birth is 29-10-1990, then your bhagyank is 4 (2+9+1+0+1+9+9+0=31, 3+1=4)
Find Namank :Â The sum of digits, that is assigned to each character for your name. Please find the following images for more details
Following is the code of how to find namank using C programming language
#include<stdio.h> #include<conio.h> #include<string.h> void main() { int a=0,i,r=0,sum=0,t; char str[20],ch; clrscr(); printf("Enter String\n"); gets(str); strlwr(str); for(i=0;str[i]!='\0';i++) { ch=str[i]; switch(ch) { case 'a': case 'i': case 'j': case 'q': case 'y': a+=1; break; case 'b': case 'k': case 'r': a+=2; break; case 'c': case 'g': case 'l': case 's': a+=3; break; case 'd': case 'm': case 't': a+=4; break; case 'e': case 'h': case 'n': case 'x': a+=5; break; case 'u': case 'v': case 'w': a+=6; break; case 'o': case 'z': a+=7; break; case 'f': case 'p': a+=8; break; default: printf("thanks"); break; } } printf("%d\n",a); if(a>9) { t = a; while (t != 0) /*login to find namank*/ { r = t % 10; sum = sum +r; t = t / 10; } printf("Sum of digits of %d = %d\n",a,sum); } getch(); }